Jfcr vx qctf zay rm umy kcytd.

E dcgf dcurb keyd kdetd ym wmauy, zay dcgf um tjmytd.

E dcgf um iflb cur xfy E jau.

Eq kf kfjf jficyfr xma'r zf ydf bmu mq vx bmu.

hint: I've deciphered this one, and as far as I can tell there was absolutely no code. Just a random substitution of letters. Once deciphered it is a riddle. The answer is some tangible object. If you get bored, give it a shot.